IP SUBNETTING

/24 - 2>8 - 255.255.255.0       
/25 - 2>7 - 255.255.255.128
/26 - 2>6 - 255.255.255.192
/27 - 2>5 -255.255.255.224
/28 - 2>4 - 255.255.255.240
/29 - 2>3 - 255.255.255.248
/30 - 2>2 - 255.255.255.252
/31 -2>1- 255.255.255.254


Class A - 0 - 126 -- 10.0.0.0 - 10.255.255.255
Class B - 128 -191 -- 172.16.0.0 - 172.31.255.255
Class C - 192 - 223 -- 192.168.0.0 - 192.168.255.255
Class D - 224 - 239 224.0.0.0 -  Mulicast
Class E - 240 -254 research 


1.)

192.168.10.0/27 

255.255.255.224

How many networks - 224/(2^5) = 7

Network address 192.168.10.0
Broadcast address 192.168.10.31
Hosts 192.168.10.1 - 192.168.10.30
How many hosts per network - 30 (32-2)

192.168.10.0
192.168.10.32
192.168.10.64
192.168.10.96
192.168.10.128
192.168.10.160
192.168.10.192
192.168.10.224

2.)


192.168.10.0/28

255.255.255.240

How many networks - 240/ ( 2^4) = 15

Network address 192.168.10.0
Broadcast adddress 192.168.10.15
Hosts 192.168.10.1 - 192.168.10.14
How many hosts per network - 14 (16-2)

192.168.10.0
192.168.10.16
192.168.10.32
192.168.10.48
192.168.10.64
192.168.10.80
192.168.10.96
192.168.10.112
192.168.10.128
192.168.10.144
192.168.10.160
192.168.10.176
192.168.10.192
192.168.10.208
192.168.10.224
192.168.10.240